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matlab code and GA code for minimum cell cost and the stepping stone method

by | Nov 30, 2023 | questions

matlab code for solving the initial feasible solution and the stepping stone method for both balanced and unbalanced transport problem. Genetic Algorithm codes for the optimal solution for the TP problem and to compare the two method stepping stone and Ga results obtained. And finally available graphs of the optimal solution

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QUESTION 1
Minimize Z = 36 X1A + 24X1B + 10X1C + 20X1D – PLANT 1
+ 30X2A + 20X2B + 8 X2C + 17X2D – PLANT 2
+ 45X3A + 30X3B + 13X3C + 25X3D – PLANT 3
Subject to
X1A + X1B + X1C + X1D = 1,000000
X2A + X2B + X2C + X2D = 1,200000
X3A + X3B + X3C + X3D = 800,000
X1A + X2A + X3A + X4A = 900, 000
X1B + X2B + X3B + X4B = 800, 000
X1C + X2C + X3C + X4C = 500,000
X1D + X2D + X3D + X4D = 800, 000
The minimum cell cost initial basic feasible solution
SOURCE
A
B
C
D
SUPPLY
PLANT 1
36
24
10
20
1000000
PLANT 2
30
20
8
17
1200000
PLANT 3
45
30
13
25
800000
Demand
900,000
800,000
500,000
800,000
3000000
To develop the path for the stepping-stone we allocate arbitrary zero to cell X1D
QUESTION 2
Minimize Z=
2X1A + 2X1B + 3X1C + 12X1D + 30X1E + 4X1F + 30X1G + 24X1H – PLANT 1
+ X2A + 6X2B + 2X2C + 6X2D + 15X2E + 2X2F + 15X2G + 12X2H – PLANT 2
+ X3A + 8X3B + 2X3C + 8X3D + 19X3E + 3X3F + 19X3G + 15X3H – PLANT 3
+ 3X4A + 20X4B + 5X4C + 20X4D + 50X2E + 7X4F + 50X4G + 40X4H – PLANT 4
Subject to
X1A + X1B + X1C + X1D + X1E + X1F + X1G+ X1H = 500000
X2A + X2B + X2C + X2D + X2E + X2F + X2G+ X2H = 1000000
X3A + X3B + X3C + X3D + X3E + X3F + X3G+ X3H = 800, 000
X4A + X4B + X4C + X4D + X4E + X4F + X4G+ X4H = 300, 000
X1A + X2A + X3A + X4A + X5A + X6A + X7A + X8A = 100, 000
X1B + X2B + X3B + X4B + X5B + X6B + X7A + X8A = 200, 000
X1C + X2C + X3C + X4C + X5C + X6C + X7C + X8C = 300,000
X1D + X2D + X3D + X4D + X5D + X6D + X7D + X8D = 400, 000
X1E + X2E + X3E + X4E + X5E + X6E + X7E + X8E = 600, 000
X1F + X2F + X3F + X4F + X5F + X6F + X7F + X8F = 200, 000
X1G + X2G + X3G + X4G + X5G + X6G + X7G + X8G = 500, 000
X1H + X2H + X3H + X4H + X5H + X6H + X7H + X8H = 300, 000
Using the minimum cell cost for the below transportation table we obtain
SOURCE
A
B
C
D
…

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