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Peak column density given temperature and linewidth

by | Nov 30, 2023 | questions

HI (21cm) emissions from a nearby galaxy are detected at three locations:

(C) – galaxy centre

(E) – -10 arcmin to the east of the galaxy center

(W) –-10 arcmin to the west of the galaxy center

The emission peaks at 21.190 cm at (C), 21.204 cm at (W), and 21.176 cm at (E).


(a) For a Hubble constant of 70 km/sec/Mpc, how far away is this galaxy (in Mpc)?

(b) How fast is the galaxy rotating? Assume that the galaxy is seen edge-on.

(c) Assuming the gas is on circular orbits, use Newton’s law of gravity to determine the amount of mass in the galaxy interior to 10 arcmin radius.

(d) The peak brightness temperature at location (C) is 12K – what is the peak column density of this galaxy at this location?


I have answers for a), b), and c) which need to be checked (attached). I am unsure of how to attempt d).

Document Preview:

HI (21cm) emissions from a nearby galaxy are detected at three locations: (C) – galaxy centre (E) – -10 arcmin to the east of the galaxy center (W) –-10 arcmin to the west of the galaxy center The emission peaks at 21.190 cm at (C), 21.204 cm at (W), and 21.176 cm at (E). (a) For a Hubble constant of 70 km/sec/Mpc, how far away is this galaxy (in Mpc)? Calculate redshift: z = (obs /emit) /emit z = (21.190 /21.106) /21.106 z = 0.0475 Calculate distance d ~ cz/H0 d ~ (c * 0.0475) /70 d ~ 203Mpc Distance is approx 203Mpc (b) How fast is the galaxy rotating? Assume that the galaxy is seen edge-on. f = c /w f(21.204cm) = 1.4138Ghz f(21.176cm) = 1.4157Ghz Width = 0.0019 v = (0.0019 /1.4138) * c v = 402.88985 km/s (c) Assuming the gas is on circular orbits, use Newton’s law of gravity to determine the amount of mass in the galaxy interior to 10 arcmin radius. M = (v^2 * r) /G r = d * angle * (Pi/180) r = 1.8221×10^19 km M = 402^2 * 1.8221×10^19 /G M = 4.412×10^34 kg M = 22,181 M_sun (d) The peak brightness temperature at location (C) is 12K -what is the peak column density of this galaxy at this location? ???

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