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Question:                 &…

by | Nov 30, 2023 | Posted Questions



                    1.
As part of a study on the effects of flu, some doctors took the
temperatures of 200 flu patients in their third day of illness.
                

                

                    a.)
What is the median (50th percentile) temperature of the 200 flu
patients?

           –
99.5; I believe that’s the correct answer…

b.) From another part of the hospital, another 50 patients are
found to have temperatures between 96 and 98. These patients are
combined with the rest and a
                    new
histogram is drawn for all 250 patients. The height of the
rectangle with base 96-98 degrees becomes _______ % per degree.
                

                

                    Question:                 &...
                

                

                    –
I’m not sure about what to do. Height = Percentage / Length of the
interval
                

                

                    The
length is “2 Degrees,” but how do you find out the
percentage?

Percentage = (# of patients who have temperatures between 96 and
98) / (# of all patients = 250)

# of patients who have temperatures between 96 and 98 = (# of
patients who have temperatures between 96 and 98 originally) + (#
of patients who have temperatures between 96 and 98 in another part
of the hospital = 50)

– I am unable to figure out the “# of patients who have
tempratures between 96 and 98 originally)

Can someone please help me out with this? I know for sure that
the answer is not 5%, 10%, 20%, or 30%.

                

                

                    Please
and thank you in advance!! ^^
                

                
                    

Show transcribed image text As part of a study on the effects of flu, some doctors took the temperatures of 200 flu patients in their third day of illness. What is the median (50th percentile) temperature of the 200 flu patients? – 99.5; I believe that's the correct answer… From another part of the hospital, another 50 patients are found to have temperatures between 96 and 98. These patients are combined with the rest and a new histogram is drawn for all 250 patients. The height of the rectangle with base 96-98 degrees becomes % per degree. – I'm not sure about what to do. Height = Percentage / Length of the interval The length is "2 Degrees," but how do you find out the percentage? Percentage = (# of patients who have temperatures between 96 and 98) / (# of all patients = 250) # of patients who have temperatures between 96 and 98 = (# of patients who have temperatures between 96 and 98 originally) + (# of patients who have temperatures between 96 and 98 in another part of the hospital = 50) – I am unable to figure out the "# of patients who have temperature between 96 and 98 originally) Can someone please help me out with this? I know for sure that the answer is not 5%, 10%, 20%, or 30%.

As part of a study on the effects of flu, some doctors took the temperatures of 200 flu patients in their third day of illness. What is the median (50th percentile) temperature of the 200 flu patients? – 99.5; I believe that's the correct answer… From another part of the hospital, another 50 patients are found to have temperatures between 96 and 98. These patients are combined with the rest and a new histogram is drawn for all 250 patients. The height of the rectangle with base 96-98 degrees becomes % per degree. – I'm not sure about what to do. Height = Percentage / Length of the interval The length is "2 Degrees," but how do you find out the percentage? Percentage = (# of patients who have temperatures between 96 and 98) / (# of all patients = 250) # of patients who have temperatures between 96 and 98 = (# of patients who have temperatures between 96 and 98 originally) + (# of patients who have temperatures between 96 and 98 in another part of the hospital = 50) – I am unable to figure out the "# of patients who have temperature between 96 and 98 originally) Can someone please help me out with this? I know for sure that the answer is not 5%, 10%, 20%, or 30%.

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