17. (16 Points) A male rabbit with long ear and gray fur mated with a female with short ear and brown fur. They produced 20 F1 rabbits. All have long ear and brown fur. The F1 were mated with each others and produced 400 F2 rabbits with the following phenotypes: 225 brown long 75 brown short 66 gray long 16 white short 9 white long 9 gray short a. (4 points)How many genes determine rabbit ear length? Show your work and circle your answer. -Because the F2 distribution is 3 long: 1 short (2 points), the ear length is determined by one gene (2 points) A-: long aa: short b. (6 points) How many genes determine rabbit fur color? Show your work and circle your answer. -The rabbit fur color is determined by two genes (2 points) because the F2 distribution is 12 brown: 3 gray: 1 white (4 points). These two genes B and C are independently assorted. bbcc: white B-cc: gray B-C- and bbC-: brown c. (6 points)What is/are the genotype(s) of the F1 rabbits? -If A is dependently assorted to both B and C, there would be 4*1/16* 400 =1/64* 400 = 6.25 white short rabbit (or there would be 3/4*1/16* 400 =1/64* 400 = 18.75 white long rabbit). -A and C must be independently assorted because there are 12/16* 34* 400 = 225 brown long (or If A and B are independently assorted, there would be 3/16 * 4 * 400 = 18.75 gray short.) Therefore, A and B are linked. -F2 aa bb cc (white short) = 2/5 *2/5 *1/4 = 1/25. Therefore, ab/ab = 4/25. p[ab gamete] = 0.4 A and B is 20mu apart (1 points) F1 genotype: AB/ab; Cc (5 points)