8
0.23529411764705882

6
0.17647058823529413

3
8.8235294117647065E-2

9
0.26470588235294118

8
0.23529411764705882

48
44
67
38

88
98
91
35

47
76
84
82

39
84
38
42

45
54
75
80

4946

4808

2673

29036

520

325
186
511

190
169
359

515
355
870

0
0.08

1
0.24

2
0.21

3
0.17

4
0.03

5
0.15

6
0.09

7
0.03

1

69.7

2.6

18.5

0.35

50

100

680
22.7

660

15
659

125
1635

285
0.9

35.6
19.2
19.2
24.2
20.3

20.100000000000001
18.5
18.8
19
20.399999999999999

18.100000000000001
18.899999999999999
17.7
19.600000000000001
19.600000000000001

21.3
18.600000000000001
21
18.600000000000001
19.899999999999999

20.100000000000001
18.399999999999999
19.3
19.399999999999999
19

0.8

0.95

1188

37
1228
20

0.05

64
62

68
72

75
79

97
57

90
91

55
56

68
88

64
89

91
77

95
75

0.05

3.5
3.5

3.8
3.6

3.9
3.5

3.7
3.9

4
3.5

4
3.7

3.6
3.6

3.9
3.6

3.7
5

3.6

Employment
Frequency
Relative Frequency
Teacher
Doctor
Scientist
Police Officer
Athlete
Q1
Q2
Q3
Min
Max
Find
Mean
Variance
Age in Years
Number of Students (f)
Under 21
21 – 25
26 – 30
Over 35
Attended College
Did not Attend
Total
Satisfied with job
Not satisfied with job
Houses sold (x)
Probability P(x)
Fill in the following blanks
and
inches tall.
the mean height of 18 -24 year old American males is
and the standard deviation is
According to the U.S. National Center for Health Statistics,
heights are normally distributed,
Determine the mean and standard deviation of the distribution of the sample mean if
the average age of freshman college students is
mean
standard deviation
n
Suppose net weights are normally distributed and the actual mean net weight Âľ =
with a standard deviation of
and a standard deviation of
is
Each year a large university collects data on average beginning monthly salaries of its business school graduates. A random sample of
recent graduates with bachelor’s degrees in marketing has a mean stating…