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Trigonometry, Help me please!

by | Nov 29, 2023 | questions

I am new to trig. The way i learn is to see how it is done then i can normally figure it out after that. Any help would be appreciated. Thank You. I am enclosing the questions in the attachments area.

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Will you please Show the Work.

1. (1 point) If tan(() > 0 then in which quadrants can ( lie?

2. (1 point) If cos(() = .15 then what are sin(() and cot(()?

3. (1 point) Is it possible for cos(() = .15 and sin(() = .85? Why?

4. (1 point) Convert 3.5( to degrees, hours and minutes.

5. (1 point) Find the exact values of csc(60() and cot(45().

6. (1 point) Is it true that sin(120() = sin(150() – sin(30()?

7. (1 point) If you take a pendulum and move it ( degrees from its equilibrium position, the force pulling it back to equilibrium is given by F = -mg sin((). Where m is the mass of the pendulum and g is the rate of acceleration due to gravity, i.e. g = 9.8
m /s2. If a pendulum is pulled 60( from its stable position and it weighs 5 kg, what will be the magnitude of the force pulling it back to its equilibrium position?

8. (1 point) Referring to question seven, does the force increase or decrease as ( increases from 0( to 90(? Why?

9. (2 points) Fill in the missing values:

( sin(() cos(() tan(() sec(() csc(() cot(() 150( 2
issing values:

( sin(() cos(() tan(() sec(() csc(() cot(() 150( 2
hich quadrants can ( lie?

2. (1 point) If cos(() = .15 then what are sin(() and cot(()?

3. (1 point) Is it possible for cos(() = .15 and sin(() = .85? Why?

4. (1 point) Convert 3.5( to degrees, hours and minutes.

5. (1 point) Find the exact values of csc(60() and cot(45().

6. (1 point) Is it true that sin(120() = sin(150() – sin(30()?

7. (1 point) If you take a pendulum and move it ( degrees from its equilibrium position, the force pulling it back to equilibrium is given by F = -mg sin((). Where m is the mass of the pendulum and g is the rate of acceleration due to gravity, i.e. g = 9.8
m /s2. If a pendulum is pulled 60( from its stable position and it weighs 5 kg, what will be the magnitude of the force pulling…

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